SOLUTION: divide 105in to two parts in which the first half part exceeds the one fifth of the second by 35'kindlygive me its step also
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Question 831338: divide 105in to two parts in which the first half part exceeds the one fifth of the second by 35'kindlygive me its step also Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! divide 105in to two parts in which the first half part exceeds the one fifth of the second by 35"
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x + y = 105"
y-(1/5)x = 35
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Substitute for "y" and solve for "x":
x + (1/5)x +35 = 105
(6/5)x = 70
x = (5/6)70
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x = 350/6
x = 58 1/3"
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y = 105 - 58 1/3 = 46 2/3 inches
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Cheers,
Stan H.
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