SOLUTION: Q1. 2^x=1/2 Q2. By considering powers of 2, solve the following equation 0.25^x=32^(3-x)
Algebra
->
Finance
-> SOLUTION: Q1. 2^x=1/2 Q2. By considering powers of 2, solve the following equation 0.25^x=32^(3-x)
Log On
Algebra in Finance
Algebra
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Finance
Question 805566
:
Q1. 2^x=1/2
Q2. By considering powers of 2, solve the following equation
0.25^x=32^(3-x)
Answer by
mananth(16946)
(
Show Source
):
You can
put this solution on YOUR website!
2^x=1/2
x=-1
Q2. By considering powers of 2, solve the following equation
0.25^x=32^(3-x)
(1/4)^x= 32^(3-x)
(1/2^2)^x= 2^5(3-x)
2^-2x = 2^(5(3-x))
-2x=5(3-x)
-2x=15-5x
3x= 15
x=5