SOLUTION: A triangular building lot is at a intersection of 2 roads which meet at an angle of 108 degrees. The frontage on one street is 15.8 meters and the frontage on the second street is

(a)  To solve (a), use this formula for the triangle area


          area = ,


     where 'a' and 'b' are two given sides of the triangle and 'C' is the angle 
     between these sides.  In your case it works this way


          area =  =  = 75.181 m^2  (rounded).



(b)  To solve (b), use the cosine law formula.  It allows to calculate the side 'c'
     of the triangle, when two other sides 'a' and 'b' are given and the angle 'C'
     between 'a' and 'b' is known


         c =  =  = 


           =  = 21.29 meters  (rounded).