SOLUTION: A block of mass 120 g moves with a speed of
6.0 m/s on a frictionaless horizontal surface
towards another block ofmass 180 g kept at rest.
They collide and the first block stops
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-> SOLUTION: A block of mass 120 g moves with a speed of
6.0 m/s on a frictionaless horizontal surface
towards another block ofmass 180 g kept at rest.
They collide and the first block stops
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Question 732219: A block of mass 120 g moves with a speed of
6.0 m/s on a frictionaless horizontal surface
towards another block ofmass 180 g kept at rest.
They collide and the first block stops. Find the
speed of the other block after the collision.
send me step by step solution Found 2 solutions by lynnlo, ikleyn:Answer by lynnlo(4176) (Show Source):
You can put this solution on YOUR website! .
A block of mass 120 g moves with a speed of 6.0 m/s on a frictionless horizontal surface
towards another block of mass 180 g kept at rest.
They collide and the first block stops. Find the speed of the other block after the collision.
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Use the law of the momentum conservation
120*6 = 180*v,
where v is the speed of the block of the mass 180 g.
From this equation
v = = = 2*2 = 4 m/s.
ANSWER. The speed of the other block after the collision is 4 m/s.
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