SOLUTION: Find the vertex, the line of symmetry and the maximum or minimum value of f(x)=1/4(x+8)^2+8. Graph the function.
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-> SOLUTION: Find the vertex, the line of symmetry and the maximum or minimum value of f(x)=1/4(x+8)^2+8. Graph the function.
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Question 515504: Find the vertex, the line of symmetry and the maximum or minimum value of f(x)=1/4(x+8)^2+8. Graph the function. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the vertex, the line of symmetry and the maximum or minimum value of f(x)=1/4(x+8)^2+8. Graph the function.
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given equation is that of a parabola of standard form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex and the parabola opens upwards.
For given equation: f(x)=1/4(x+8)^2+8
vertex: (-8,8)
line of symmetry: x=-8
since parabola opens upwards, there is a minimum of 8
see graph below:
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