Question 315602: Find an equation of the line containing the points (-3, 1) and (-1, 3). Found 3 solutions by jim_thompson5910, nyc_function, stanbon:Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! We first find the slope.
Let m = slope
m = (3 - 1)/(-1 -(-3))
m = 2/(-1 + 3)
m = 2/2
m = 1
The slope is 1.
We now use the point-slope formula.
y - y1 = m(x - x1)
Pick one of the given points and the slope 1 to plug into the poitn-slope formula.
y - 1 = 1(x - (-3))
y - 1 = 1(x + 3)
y - 1 = x + 3
y = x + 3 + 1
y = x + 4
Done!
You can put this solution on YOUR website! Find an equation of the line containing the points (-3, 1) and (-1, 3).
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slope = (3-1)/(-1--3) = 2/2 = 1
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Form: y = mx + b
You know m = 1 and y = 1 when x = -3 ; solve for "b":
1 = 1*-3 + b
b = 4
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Equation:
y = x + 4
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Cheers,
Stan H.