SOLUTION: how many liters of 40% solution has to be added to 10 leiters of 80% to make 60%? I need linier equations with 2 viariables to solve

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Question 297117: how many liters of 40% solution has to be added to 10 leiters of 80% to make 60%?
I need linier equations with 2 viariables to solve

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = liters of 40% solution needed
Let y = liters of 60% solution you end up with
given:
(1) y+=+x+%2B+10
(2) %28.4x+%2B+.8%2A10%29%2Fy+=+.6
-------------------------------------
from (2),
(2) .4x+%2B+.8%2A10+=+.6y
6y+=+4x+%2B+80
-----------------------
y+=+%282%2F3%29%2Ax+%2B+40%2F3
and
y+=+x+%2B+10 answers
--------------------------
check answers:
%282%2F3%29%2Ax+%2B+40%2F3+=+x+%2B+10
2x+%2B+40+=+3x+%2B+30
x+=+10
and, since
y+=+x+%2B+10
y+=+20
(2) %28.4x+%2B+.8%2A10%29%2Fy+=+.6
(2) %28.4%2A10+%2B+.8%2A10%29%2F20+=+.6
%284+%2B+8%29%2F20+=+.6
12%2F20+=+.6
12+=+12
OK