SOLUTION: if A's income is 20% more than B's income, how much percent is B's income less than A's income
Algebra
->
Finance
-> SOLUTION: if A's income is 20% more than B's income, how much percent is B's income less than A's income
Log On
Algebra in Finance
Algebra
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Finance
Question 242353
:
if A's income is 20% more than B's income, how much percent is B's income less than A's income
Answer by
Theo(13342)
(
Show Source
):
You can
put this solution on YOUR website!
Let A = income that A makes.
Let B = income that B makes.
Percent difference in income that A makes compared to B would be equal to (A-B)/B * 100%
Percent difference in income that B makes compared to A would be equal to (B-A)/A * 100%
Assume A makes 120 dollars and B makes 100 dollars.
(A-B)/B = (120-100)/100 = 20/100 = .2 * 100% = 20%
This is equivalent to 20% more than what A makes.
(B-A)/A = (100-120)/120 = -20/120 = -.167 * 100% = -16.7% (rounded)
This is equivalent to 16.7% less than what B makes.
It's the same difference in income ($20).
The denominator is different.
Percent of B's income, then B's income is the denominator.
Percent of A's income, then A's income is the denominator.