SOLUTION: the task is 3/7 = 2/x-4
i solved as follows: 0=(2/x-4)/(3/7) = 2/(x-4)*(7/3) now the result would be 14/3x-12 but I know that this is the wrong answer... where is my mistake?
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-> SOLUTION: the task is 3/7 = 2/x-4
i solved as follows: 0=(2/x-4)/(3/7) = 2/(x-4)*(7/3) now the result would be 14/3x-12 but I know that this is the wrong answer... where is my mistake?
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Question 193082: the task is 3/7 = 2/x-4
i solved as follows: 0=(2/x-4)/(3/7) = 2/(x-4)*(7/3) now the result would be 14/3x-12 but I know that this is the wrong answer... where is my mistake? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! the task is 3/7 = 2/x-4
i solved as follows: 0=(2/x-4)/(3/7) = 2/(x-4)*(7/3) now the result would be 14/3x-12 but I know that this is the wrong answer... where is my mistake?
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You divided by (3/7), which makes it = 1, not zero.
3/7 = 2/x-4
Cross multiply
3*(x-4) = 14
3x-12 = 14
3x = 26
x = 26/3
