SOLUTION: I have used the solvers presented but I am unable to get the correct answer for the following: A man invest $7000 for one year. He invested part of it at 8% and the rest at 12%.
Algebra ->
Finance
-> SOLUTION: I have used the solvers presented but I am unable to get the correct answer for the following: A man invest $7000 for one year. He invested part of it at 8% and the rest at 12%.
Log On
Question 189605: I have used the solvers presented but I am unable to get the correct answer for the following: A man invest $7000 for one year. He invested part of it at 8% and the rest at 12%. At the end of the year he earned $764 in interest. How much did he invest at each rate? This is a quiz question. Answer by jim_thompson5910(35256) (Show Source):
"He invested part of it at 8% and the rest at 12%. At the end of the year he earned $764 in interest" translates to
Multiply every term by 100 to get
So we have the system
Let's solve this system by substitution
Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.
So let's isolate y in the first equation
Start with the first equation
Subtract from both sides
Rearrange the equation
---------------------
Since , we can now replace each in the second equation with to solve for
Plug in into the second equation. In other words, replace each with . Notice we've eliminated the variables. So we now have a simple equation with one unknown.