SOLUTION: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. Hint: You did this in Module 3 Assignment 8. Now you have to write the equation

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Question 147899: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. Hint: You did this in Module 3 Assignment 8. Now you have to write the equation and solve it.
I need help :)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 3 more than twice its width.
1.L=3%2B2W
The perimeter is 48 feet.
P=48
In terms of length and width, the perimeter of a rectangle is,
P=2L%2B2W
2.2L%2B2W=48
Use eq. 1 and substitute into eq. 2 for L,
2.2L%2B2W=48
2%283%2B2W%29%2B2W=48
6%2B4W%2B2W=48
6%2B6W=48
6W=42
W=7
Now use eq. 1 to solve for L.
1.L=3%2B2W
L=3%2B2%287%29
L=3%2B14
L=17