SOLUTION: The length of rectangle is fixed at 11cm. what widths will make the permeter greater than 92cm? 11x-9<-53 =? 6(3+4x)-8>154= Please help!

Algebra ->  Finance -> SOLUTION: The length of rectangle is fixed at 11cm. what widths will make the permeter greater than 92cm? 11x-9<-53 =? 6(3+4x)-8>154= Please help!      Log On


   

Question 144400: The length of rectangle is fixed at 11cm. what widths will make the permeter greater than 92cm?
11x-9<-53 =?
6(3+4x)-8>154=
Please help!
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter = 2*length + 2* width
92%3C+2%2Al+%2B+2%2Aw
92+%3C+2%2A11+%2B+2%2Aw
92+%3C+22+%2B+2w+
70+%3C+2w
35+%3C+w+ so any width larger than 35cm will do

11x-9<-53
11x < -44
x < -4


6(3+4x)-8>154
18 + 24x -8 > 154
10 + 24x > 154
24x > 144
x > 6