SOLUTION: Hi, can someone help me with this problem? Solve for x and y: 2x + 3y = 1 5x + 3y = 16 Thanks.

Algebra ->  Finance -> SOLUTION: Hi, can someone help me with this problem? Solve for x and y: 2x + 3y = 1 5x + 3y = 16 Thanks.      Log On


   



Question 143797: Hi, can someone help me with this problem?
Solve for x and y: 2x + 3y = 1
5x + 3y = 16
Thanks.

Answer by nabla(475) About Me  (Show Source):
You can put this solution on YOUR website!
Let's have a little fun with this problem. Let's generalize a formula for 2 equations in 2 variables!
consider:
ax+by=c
dx+ey=f
let's solve each for y!
y=(c-ax)/b
y=(f-dx)/e
Now, we need to find where they are equal.
(f-dx)/e=(c-ax)/b
This gives:
b(f-dx)=e(c-ax)
and thus
bf-bdx=ec-eax
eax-bdx=ec-bf
x=(ec-bf)/(ea-bd)
moreover y=(c-a(ec-bf)/(ea-bd))/b.
It is very constructive to do exercises like this to build understanding.
In any case, let's apply the formulae to your equations:
x=(3*1-3*16)/(3*2-3*5)=(3-48)/(6-15)=-45/-9=5 !!!
Thus y=(c-ax)/b=(1-2(5))/3=-3.
Giving us solution set (5,-3).
Now, something more in keeping with what your instructor will want:
2x + 3y = 1
5x + 3y = 16
subtract the second equation from the first
-3x=-15
gives x=5
put x=5 into the first equation
2(5)+3y=1
3y=-9
y=-3
Another way would be through substitution:
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++2%5Cx+%2B+3%5Cy+=+1%2C%0D%0A++++5%5Cx+%2B+3%5Cy+=+16+%29%0D%0A++We'll use substitution. After moving 3*y to the right, we get:
2%2Ax+=+1+-+3%2Ay, or x+=+1%2F2+-+3%2Ay%2F2. Substitute that
into another equation:
5%2A%281%2F2+-+3%2Ay%2F2%29+%2B+3%5Cy+=+16 and simplify: So, we know that y=-3. Since x+=+1%2F2+-+3%2Ay%2F2, x=5.

Answer: system%28+x=5%2C+y=-3+%29.


If you have any questions, now or in the future, send me an E-mail at enabla@gmail.com.