SOLUTION: Please help me answer this! it's very important! :] Andrea purchased a picture frame for $14.56. This price was a 30% markup from the wholesale cost. What was the wholesale

Algebra ->  Finance -> SOLUTION: Please help me answer this! it's very important! :] Andrea purchased a picture frame for $14.56. This price was a 30% markup from the wholesale cost. What was the wholesale       Log On


   



Question 143168: Please help me answer this! it's very important! :]

Andrea purchased a picture frame for $14.56. This price was a 30% markup from the wholesale cost. What was the wholesale cost?

Answer by zephyr(9) About Me  (Show Source):
You can put this solution on YOUR website!
If I read the question right. Then your work should look like this.
14.56%2Fn=130%2F100
14.56 = the markup.
n = the original price, and because this is a markup, n = 100%.
Since 14.56 markup, it's the original price (100%) + the markup percentage (30%) which equals 130%, so that means 14.56 is 130% of the original price.
Now we cross multiply to find N
(and since you're not supposed to multiply n in this type of equation, you multiply the 2 numbers that are diagonal to each other...in other words, you do this.)
14.56%2A100=1456
and you divide it by the remaining number. (which happens to be 130)
1456%2F130=11.20 Therefore, the Wholesale price was $11.20.
(I hope that wasn't too confusing. Hope it helped!)
(Note: in this type of equation, you will always have 100 on the bottom right. For example, if you were finding something that had a markdown, it would be
n%2Foriginal+price=percentage+decreased%2F100 Say, something that cost $10 was on sale, and you bought it at 1/2 price. That would be
n%2F10=50%2F100
then you would multiply 10 by 50 (10%2A50=500) then you would divide by 100. (500%2F100=5) and then $5 would be your answer)