SOLUTION: $3000 is deposited at 8% compounded semiannually. How long does it take to double? Round to the nearest tenth of a year.
Use the formula
A=P(1+r/n)^nt
possible answers
1.) 8.8
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-> SOLUTION: $3000 is deposited at 8% compounded semiannually. How long does it take to double? Round to the nearest tenth of a year.
Use the formula
A=P(1+r/n)^nt
possible answers
1.) 8.8
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Question 1209221: $3000 is deposited at 8% compounded semiannually. How long does it take to double? Round to the nearest tenth of a year.
Use the formula
A=P(1+r/n)^nt
possible answers
1.) 8.8 years
2.) 9.2 years
3.) 9 years
4.) 8.6 years Found 2 solutions by math_tutor2020, ikleyn:Answer by math_tutor2020(3817) (Show Source):
Work Shown
P = 3000 is the investment amount. We wish to double it to A = 6000 dollars.
r = 0.08 = decimal form of the annual interest rate
n = 2 since we're compounding 2 times a year
The goal is to solve for t.
A = P(1+r/n)^(nt)
6000 = 3000(1+0.08/2)^(2*t)
6000/3000 = (1.04)^(2*t)
2 = (1.04)^(2*t)
Log(2) = Log( (1.04)^(2*t) )
Log(2) = 2t*Log(1.04)
t = (1/2)*Log(2)/Log(1.04)
t = 8.836494 approximately
t = 8.8 years when rounding to the nearest tenth of a year.
Footnotes:
Use logs to isolate the variable exponent. A useful phrase to remember is "When the variable is in the trees we log it down".
I used the rule Log(x^y) = y*Log(x) which allows us to pull down the exponent.
The logs can be any valid base. Perhaps base 10 is easiest to work with.
The 3000 doesn't affect the answer. We can change the 3000 to any positive number we want, and get the same result at the end.
Upon thinking about it more, it doesn't make much sense to round to the nearest tenth. It would be best to round to the nearest half (since we're compounding the money every half a year). However, I'll stick with the answer 8.8 since that appears to be what the teacher wants.
Calculations that brought tutor @math_tutor2020 to the value t = 8.83... years (approximately)
were correct, but the conclusion, which he made from it was wrong.
The discretely compounded amount is not a continuous function of time.
The amount of a discretely compounded account is a discontinuous function.
It is changed jumping at the compounding time moments.
So, the value t= 8.83... years MUST be rounded UP to the closest compounding time period,
in order for the bank would be in position to make the last compounding.
Thus the correct answer to this problem is 9 years.
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