SOLUTION: To start the construction of a rest house in tagaytay, the engineer advice his foreman to erect five pegs to establish the perimeter (outside) of the floor plan, which is in the sh
Algebra ->
Finance
-> SOLUTION: To start the construction of a rest house in tagaytay, the engineer advice his foreman to erect five pegs to establish the perimeter (outside) of the floor plan, which is in the sh
Log On
Question 1204003: To start the construction of a rest house in tagaytay, the engineer advice his foreman to erect five pegs to establish the perimeter (outside) of the floor plan, which is in the shape of a regular pentagon. The desired area of the floor plan is 80 squared meters. Find the length of the string needed in the layout. Consider that 5 percent is accounted for tying. Answer by Theo(13342) (Show Source):
the expression under the square root sign becomes equal to 6.881909602.
the formula becomes A = 1/4 * 6.881909602 * a^2.
solve for a^2 to get a^2 = 4 * A / 6.881909602.
when A = 80, this becomes a^2 = 4 * 80 / 6.881909602 = 46.49872179.
solve for a to get a = square root of 46.49872179 = 6.818997125.
the perimeter of the pentagon is 5 times that = 34.40954801.
add 5% to that to get 35.79973491.
the minimum length of string you'll need has a length of 35.79973491 meters.
that's your solution.
