You can put this solution on YOUR website! .
A field has an area of x^2 + x-6. State the expressions for its length and width.
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The problem formulation is not precisely correct,
because there are infinitely many answers - - - much more answers than one.
One possible answer is x^2 + x - 6 = (x^2 + x - 6)*1, giving the dimensions
(x^2 + x - 6) and 1 (one unit)
that are valid when the quadratic is positive (x > 2 or x < -3).
Another possible decomposition/factoring is x^2 + x - 6 = (x+3)*(x-2),
which gives the dimensions (x+3) and (x-2) linear units with x > 2.
Third possible decomposition/factoring is x^2 + x - 6 = ,
which gives the dimensions a*(x+3) and linear units with x > 2
and any real number "a".
Solved, with explanations.
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The error in the problem formulation is TYPICAL for such problems,
made by unexperienced Math problems composers, or those who copy-paste from other sources
without thinking on the subject.
I saw such errors many times (more than I can count :).
