SOLUTION: The figure below shows a vertical cross - section of a hemispherical bowl centre o. The radius OA of the bowl is 15 cm. The bowl contains water to a depth of 6 cm. Calculate the

Make a sketch.

Draw the radius of 15 cm vertically down.

Draw the water level horizontally.


Draw another radius to the edge of the water level.


In the sketch, find a right-angled triangle.


    Its hypotenuse is the slanted radius of 15 cm length.

    Its one leg is 15-6 = 9 cm long.

    Hence, the other leg is   = 12 cm.


Thus the radius of the water surface in the bowl is 12 cm.


Hence, the area of the water surface is   = 383.08 cm^2.    ANSWER