SOLUTION: If {{{M}}}{{{""=""}}}{{{(matrix(3,3,1,-1,k,4,7,3,-1,12,-2))}}} Evaluate in term of k the determinant of M. Hence, if {{{X}}}{{{""=""}}}{{{(matrix(3,1,x,y,z))}}}, Solve the equat

Algebra ->  Finance -> SOLUTION: If {{{M}}}{{{""=""}}}{{{(matrix(3,3,1,-1,k,4,7,3,-1,12,-2))}}} Evaluate in term of k the determinant of M. Hence, if {{{X}}}{{{""=""}}}{{{(matrix(3,1,x,y,z))}}}, Solve the equat      Log On


   



Question 1196243: If M%22%22=%22%22%28matrix%283%2C3%2C1%2C-1%2Ck%2C4%2C7%2C3%2C-1%2C12%2C-2%29%29
Evaluate in term of k the determinant of M.
Hence, if X%22%22=%22%22%28matrix%283%2C1%2Cx%2Cy%2Cz%29%29,
Solve the equation MX%22%22=%22%22%28matrix%283%2C1%2C1%2C11%2C21%29%29
when k = 2, by the cofactor method.

Found 2 solutions by Edwin McCravy, ikleyn:
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
The cofactor method of finding the inverse is the hardest way.
Here goes:

M%22%22=%22%22%28matrix%283%2C3%2C1%2C-1%2Ck%2C4%2C7%2C3%2C-1%2C12%2C-2%29%29

%22det%28M%29%22%22%22=%22%22abs%28matrix%283%2C3%2C1%2C-1%2Ck%2C4%2C7%2C3%2C-1%2C12%2C-2%29%29%22%22=%22%22%22%22=%22%22

%22%22=%22%22

%22%22=%22%22
%28-14-36%29%2B%28-8%2B3%29%2Bk%2848%2B7%29%22%22=%22%22-50-5%2Bk%2855%29%22%22=%22%2255k-55

In order to solve the equation 

MX%22%22=%22%22%28matrix%283%2C1%2C1%2C11%2C21%29%29

We must find the inverse of M which is written M-1 by the long,
hard, cofactor method:

We replace each element of M by the determinant of its cofactor, which is its
minor 2x2 determinant.



We put in the "checkerboard" of signs, this will be the cofactor matrix



We evaluate the determinants










%28matrix%283%2C3%2C%0D%0A%0D%0A-50%2C5%2C55%2C%0D%0A22%2C0%2C-11%2C%0D%0A-17%2C5%2C11%29%29

Next we form the adjoint or adjugate matrix which is the transpose
of the matrix of cofactors:

%28matrix%283%2C3%2C%0D%0A%0D%0A-50%2C22%2C-17%2C%0D%0A5%2C0%2C5%2C%0D%0A55%2C-11%2C11%29%29

Now we find the inverse of M by multiplying the adjoint or adjugate
by the reciprocal of the value of the determinant of M. We calculated
the value of the determinant of M in terms of k as
55k-55
But we were told to use k=2, so substituting,
55%282%29-55%22%22=%22%22110-55%22%22=%22%2255
So we multiply the adjoint or adjugate by 1%2F55


M%5E%28-1%29%22%22=%22%22%22%22=%22%22%22%22=%22%22


Next we multiply both sides of the equation we are to solve:

MX%22%22=%22%22%28matrix%283%2C1%2C1%2C11%2C21%29%29

by the inverse M-1:

M%5E%28-1%29%28MX%5E%22%22%29%22%22=%22%22%28M%5E%28-1%29M%29X%22%22=%22%22IX%22%22=%22%22X%22%22=%22%22%28matrix%283%2C1%2Cx%2Cy%2Cz%29%29%22%22=%22%22%22%22=%22%22%22%22=%22%22

%22%22=%22%22%22%22=%22%22%28matrix%283%2C1%2C%0D%0A%0D%0A-165%2F55%2C%0D%0A22%2F11%2C%0D%0A15%2F5%29%29%22%22=%22%22%28matrix%283%2C1%2C-3%2C2%2C3%29%29

So

X%22%22=%22%22%28matrix%283%2C1%2Cx%2Cy%2Cz%29%29%22%22=%22%22%28matrix%283%2C1%2C-3%2C2%2C3%29%29

Edwin


Answer by ikleyn(52781) About Me  (Show Source):