SOLUTION: Given that 0 < x < 90° and sin(x+60°) =cos(2x), find the exact value of tan(x+20°)

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Question 1195236: Given that 0 < x < 90° and sin(x+60°) =cos(2x), find the exact value of tan(x+20°)
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
See the spacings this way:
Given that 0 < x  <90° and sin(x+60)° =cos (2x)° ,find the exact value of tan(x+20)°

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Given that 0 < x < 90° and sin(x+60°) = cos(2x), find the exact value of tan(x+20°)
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Your starting equation is

    sin(x+60°) =cos(2x).         (1)


Since  cos(2x) = sin(90°-2x), you can re-write equation (2) in the next equivalent form

    sin(x+60°) = sin(90°-2x).    (2)


Since both angles, x+60° and 90°-2x are acute, equation (2) implies

    x+60° = 90°-2x.


Solve it and find x

    x + 2x = 90° - 60°,

      3x   =    30°,

       x   =    10°.


THEREFORE,  tan(x+20°) = tan(10°+20°) = tan(30°) = sqrt%283%29%2F3.


ANSWER.  If  0 < x < 90°  and  sin(x+60)° = cos(2x),  then  tan(x+20°) = sqrt%283%29%2F3.

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        Found without using a calculator or tables, but exclusively
                using the power of knowledge and intellect.

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But notice that,  without using a calculator or tables,  I found  EXACT  EXPRESSION
for  tan(x+20°),  ONLY - - - but not the value of  tan(x+20°).


It is  POSSIBLE  to find exact expression without using calculator or tables,
but it is  IMPOSSIBLE  to find the  VALUE  without using a calculator or a table.

THEREFORE,  the problem's formulation itself  IS  NOT  CORRECT.

The correct formulation should ask to find  EXACT  EXPRESSION  for  tan(x+20°),  but not the exact value of  tan(x+20°).


Today,  I saw  SEVERAL  similar posts from you for other expressions,  also asking
to find exact value without a calculator or a table.

All these formulations are  INCORRECT  due to the same reason.
Correct formulations should ask to find exact expressions,  but not about exact values.