SOLUTION: The Jurassic Zoo charges ​$12 for each adult admission and ​$7 for each child. The total bill for the 131 people from a school trip was ​$1062. How many adults and how many

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Question 1193381: The Jurassic Zoo charges ​$12 for each adult admission and ​$7 for each child. The total bill for the 131 people from a school trip was ​$1062. How many adults and how many children went to the​ zoo?  
there were _adults and _children on the trip

Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%2By=131%2C7x%2B12y=1062%29


If multiply first equation by 7, then
system%287x%2B7y=917%2C7x%2B12y=1062%29
.
.
y=29, and...

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


First we will solve the problem using logical reasoning and simple mental arithmetic, since that gives us good mental exercise.

If all 131 people were children, the total cost of admission would have been 131($7)=$917.
The actual cost, $1062, was $1062-$917 = $145 more.
The cost of each adult admission is $5 more than the cost of each child admission.
The number of adult tickets, to make the additional $145, was $145/$5=29.

ANSWER: there were 29 adults and 131-29=102 children

CHECK: 29($12)+102($7)=$348+$714=$1062

Using formal algebra....

x = # of adults
131-x = # of children

The total cost, at $12 per adult and $7 per child, was $1042:

12x%2B7%28131-x%29=1062
12x%2B917-7x=1062
5x=145
x=29

Adults: x = 29
Children: 131-x = 102

Note that with this method of solving the problem using formal algebra, the calculations are exactly the same as with the informal method.