SOLUTION: Find the equation of the hyperbola for each given conditions. d. Focus at (4,0) and eccentricity = 3/2.

Algebra ->  Finance -> SOLUTION: Find the equation of the hyperbola for each given conditions. d. Focus at (4,0) and eccentricity = 3/2.      Log On


   

Question 1191092: Find the equation of the hyperbola for each given conditions.
d. Focus at (4,0) and eccentricity = 3/2.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the equation of the hyperbola:
%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1+
eccentricity of hyperbola e+=+c%2Fa=> c=3 and a=2
b%5E2=3%5E2-2%5E2=5
focus is (h+-+c,+k+) = (4, 0 )
=>h-c=4 =>h-3=4=>h=7%0D%0Aand+%7B%7B%7Bk=0

then, center is at (7,+0+)

and your equation is:
%28x-7%29%5E2%2F4-%28y-0%29%5E2%2F5=1+
%28x-7%29%5E2%2F4-y%5E2%2F5=1+