SOLUTION: Solve for the unknown in the equation below {{{1-y/2-2((y-3)/2)=0}}}

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Question 1189121: Solve for the unknown in the equation below
1-y%2F2-2%28%28y-3%29%2F2%29=0

Found 2 solutions by Stelless, greenestamps:
Answer by Stelless(3) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for the unknown in the equation below
1-y%2F2-2%28%28y-3%29%2F2%29=0
In the third term of this equation, we are multiplying by 2 and dividing by 2. Thus we can cancel them out.
1-y%2F2-%28y-3%29%29=0
Now we should move all of our 'y' variables to one side. By adding (y/2) and (y-3) to both sides we will have
1=y%2F2%2B%28y-3%29
We now can break up the parentheses as we've simplified them as far as we can. After this will we add 3 to both sides, this way we only have terms involving 'y' on the right.
1=y%2F2%2B%28y-3%29 -> 1%2B3+=+y%2F2%2By-3%2B3
After doing this it leaves us with:

By doing this we can combine terms by adding fractions with common denominators. This will give us:
4=y%2F2+%2B+2y%2F2
simplifying we get:
4=3y%2F2
From here we solve for y by multiplying by two then diving by three.
+8%2F3=y+ or +y=8%2F3+

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


1-y%2F2-2%28%28y-3%29%2F2%29=0

Multiply by 2 to clear fractions:

2-y-2%28y-3%29=0

Distribute the -2....:

2-y-2y%2B6=0

Combine like terms and isolate the y's on one side:

8=3y
8%2F3=y

ANSWER: y=8/3