SOLUTION: Find four consecutive odd integers such that the sum of the first and second odd integer is twelve more than one-half of the sum of the third and fourth odd integer.

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Question 1188076: Find four consecutive odd integers such that the sum of the first and second odd integer is twelve more than one-half of the sum of the third and fourth odd integer.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%28n%2C+n%2B2%2C+n%2B4%2C+n%2B6%29

n%2B%28n%2B2%29=12%2B%281%2F2%29%28n%2B4%2Bn%2B6%29------literally the description

2n%2B2=12%2B%281%2F2%29%282n%2B10%29
4n%2B4=24%2B2n%2B10
2n%2B2=12%2Bn%2B5
n=15


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Integers 15, 17, 19, 21
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15%2B17=12%2B%281%2F2%29%2819%2B21%29
32=12%2B%281%2F2%2940
32=12%2B20
OK