SOLUTION: A solution was prepared by dissolving 25g of KOH in 250cm3 of distilled water. Calculate the concentration of the solution in mol dm-3 [K=39, O=16, H=1]

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Question 1186275: A solution was prepared by dissolving 25g of KOH in 250cm3 of distilled water.
Calculate the concentration of the solution in mol dm-3
[K=39, O=16, H=1]

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
Formula Weight of KOH



56 grams per mole, for KOH



1.786 moles per dm^3





***********************not this*****************************


Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
.

Molecular Weight of KOH (Potassium hydroxide) is 56.


So, 1 mole of KOH is 56 grams.


25 grams of Potassium hydroxide is   = 0.4464 of a mole.


250 cm^3 = 0.25 dm^3.


The concentration of the solution in    is,  THEREFORE,


     = 1.786 .    ANSWER

It is my answer.


----------------


I am not a chemist in my basic education,  although learned Chemistry diligently in my high school.

Working on this assignment, I consulted with Wikipedia and other Internet sources regarding properties
of KOH at normal temperature, including solubility.

I also have many years experience working with civil and mechanical engineers,  where skills and a common sense
in operating with dimensions are  MUST.


I started doing this assignment, because calculations by @josgarithmetic seem to be absurdist to me
and irrelevant to the posed question.


//////////////


After seeing my post, @josgarithmetic did what he does every time: re-wrote the numbers from my post.

So, it was not for nothing, when I worked on my solution . . .



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