SOLUTION: Two dice are thrown together once. Find the probability of obtaining: 1. an odd number on the first die and 6 on the second 2. a number greater than 4 on each dice 3. a total of

(1)  In all, there are  6*6 = 36  different possible otcomes.

     They are all the pair of integer numbers (a,b), where "a" and "b" are from 1 to 6 inclusive.


     Of these 36 pairs, the favorable are three outcomes (1,6), (3,6), (5,6).


     So, the probability is   =  = .




(2)  Again, I will not repeat about 36 total outcomes.


     The favorable are 4 pairs (a,b), where a = 5 or 6  and b = 5 or 6, independtently.


     The probability is   = .



(3)  Again, there 36 total outcomes.

     Of them, there are 4 favorable with the sum of  9  (they are the pairs (3,6), (4,5), (5,4), (6,3))

                    and 2 favorable with the sum of 11  (they are the pairs (5,6) and (6,5)).


     In all, there are 4 + 2 = 6 favorable outcomes.


     The probability is   = .