SOLUTION: A semicircular tunnel has a radius of 26 ft. The highway 48 ft wide is centered under the tunnel. a. What is the diameter of the tunnel? b. How high is the tunnel from the edge o

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Question 1182926: A semicircular tunnel has a radius of 26 ft. The highway 48 ft wide is centered under the tunnel.
a. What is the diameter of the tunnel?
b. How high is the tunnel from the edge of the highway?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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A semicircular tunnel has a radius of 26 ft. The highway 48 ft wide is centered under the tunnel.
a. What is the diameter of the tunnel?
b. How high is the tunnel from the edge of the highway?
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(a)  The diameter of the tunnel is twice its radius, i.e. 2*26 = 52 ft.        ANSWER



(b)  The height of the tunnel at its edge is  


         h = sqrt%2826%5E2+-+%2848%2F2%29%5E2%29 = sqrt%2826%5E2-24%5E2%29 = 2%2Asqrt%2813%5E2+-+12%5E2%29 = 2%2Asqrt%28169-144%29 = 2%2Asqrt%2825%29 = 2*5 = 10 ft.    ANSWER

Solved.