Question 1182198: Find the time required for an investment of 5000 pesos to grow to 7700 pesos at an interest rate of 6.5% per year, compounded quarterly. Round to the nearest year.
Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
Find the time required for an investment of 5000 pesos to grow to 7700 pesos
at an interest rate
of 6.5% per year, compounded quarterly. Round to the nearest year.
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For the amount of 5000 pesos, compounded quarterly at 6.5% per year, the future value formula is
Future Value =
where n is the number of quarters.
Therefore, our equation to find "n" is
7700 =
Divide both sides by 5000
= ,
or
1.54 = .
Take logarithm base 10 of both sides
log(1.54) = n*log(1.01625)
and find "n" using your calculator
n = = 26.77 quarters.
Finally, round this value 26.77 to the nearest greater integer 27,
in order for the bank was in position to make the last compounding.
ANSWER. 27 quarters, or 6 years and 9 months;
or, if you wat to round to the nearest year, 7 years.
Solved.
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To see many other similar (and different) solved problems, look into the lesson
- Problems on discretely compound accounts
in this site, and learn the subject from there.
After reading this lesson, you will tackle such problems on your own without asking for help from outside.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Logarithms".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
Happy learning (!)
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