SOLUTION: Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Of 82 adults selected randomly from one town, 66 have heal

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Question 1178700: Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.
Of 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The 90% confidence interval is given by
p%5B1%5D+%2B-+t%5B0.95%5D%2Asqrt%28%28p%5B1%5D%2A%281-p%5B1%5D%29%29%2Fn%29
= 66%2F82+%2B-+t%5B0.95%5D%2Asqrt%28%28%2866%2F82%29%2A%2816%2F82%29%29%2F82%29
= 66%2F82+%2B-+1.664%2Asqrt%28%28%2866%2F82%29%2A%2816%2F82%29%29%2F82%29
= [0.732, 0.878], with the endpoints rounded to 3d.p.
The t-distribution probabilities were taken from https://stattrek.com/online-calculator/t-distribution.aspx.