SOLUTION: For a certain company, the cost function for producing x items is C(x)=30x+200 and the revenue function for selling x items is R(x)=−0.5(x−110)2+6,050. The maximum capacity of

Algebra ->  Finance -> SOLUTION: For a certain company, the cost function for producing x items is C(x)=30x+200 and the revenue function for selling x items is R(x)=−0.5(x−110)2+6,050. The maximum capacity of       Log On


   



Question 1178279: For a certain company, the cost function for producing x items is C(x)=30x+200 and the revenue function for selling x items is R(x)=−0.5(x−110)2+6,050. The maximum capacity of the company is 150 items.
What is the domain of P(x)?
Hint: Does calculating P(x) make sense when x=−10 or x=1,000?
The company can choose to produce either 80 or 90 items. What is their profit for each case, and which level of production should they choose?
Profit when producing 80 items =
Number

Profit when producing 90 items =
Number

Can you explain, from our model, why the company makes less profit when producing 10 more units?

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

In order for your questions could be answered,  the post,  i.e.   Y O U ,   the author,

must define   WHAT   P(x)   is.


After that,  you may ask your questions ---- but  NOT  BEFORE  it . . .


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