SOLUTION: A man begins to trade with sh 37100 . Later on , a partner joins him , injecting sh 63600 into business. At the end of the first year’s trading, the two partners share the profit
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Question 1173658: A man begins to trade with sh 37100 . Later on , a partner joins him , injecting sh 63600 into business. At the end of the first year’s trading, the two partners share the profits equally. Find the time of the year when the second partner joined the first parter. Answer by ikleyn(52787) (Show Source):
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A man begins to trade with sh 37100 . Later on , a partner joins him , investing sh 63600 into business.
At the end of the first year’s trading, the two partners share the profits equally.
Find the time of the year when the second partner joined the first partner.
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From the context, the money of the first man worked 1 year, i.e. 365 days.
Let x be the number of days the money of the partner worked.
The contribution of the first man money's to the profit is proportional to = 365*37100 (sh*day).
The contribution of the partner money's to the profit is proportional to = x*636000 (sh*day).
(the proportionality coefficient is the "interest rate").
They divided the profit equally at the end. It means that the contributions and are equal
365*37100 = x*636000.
From this equation, find the unknown number of days x
x = = 365*0.58333 = 213 days.
So, the partner entered the business 213 days, or about 7 months, before the end of the year.
ANSWER. The partner entered the business about 5 months after the first man.
