Question 1169754: A tank containing 50 litres of water develops a leak and loses water at a constant rate. After 20 minutes it contains 40 litres. After further 30 minutes the tank is 5% of its full capacity. Determine the tank's capacity.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! Three points (x,y):
(0,50), (20,40), (30,0.05C) and C is for tank's capacity.
* MISTAKE FOUND: "After further 30 minutes,..."
That meant, 20+30=50 minutes.
The variable point should be (50,0.05C).
----------------NO, NOT THIS--------------------
slope,  ;
To find C, use the unknown point.
 ------------solve this for C.
Answer by ikleyn(52781)  (Show Source):
You can put this solution on YOUR website! .
From first two sentences, we have this equation
V(t) = 50 - a*t.
representing the current volume V(t) as a function of time, t, in minutes,
and "a" is the constant leaking rate in liters per minute.
At t= 20 minutes,
V(20) = 40 = 50 - a*20,
which gives a =  =  = 0.5 liters per minute.
After further 30 minutes, the volume of the water in the tank is
V(50) = 40 - 0.5*30 = 40 - 15 = 25 liters.
So, 25 liters is 5% of the tank capacity.
Hence, the total capacity of the tank is  = 500 liters.
ANSWER. The total capacity of the tank is = 500 liters.
Solved, answered, explained and completed.
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Do not accept nothing from the post by @josgarithmetic,
since he interprets the problem's description incorrectly.
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