SOLUTION: A tank containing 50 litres of water develops a leak and loses water at a constant rate. After 20 minutes it contains 40 litres. After further 30 minutes the tank is 5% of its full

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Question 1169752: A tank containing 50 litres of water develops a leak and loses water at a constant rate. After 20 minutes it contains 40 litres. After further 30 minutes the tank is 5% of its full capacity. Determine the tank's capacity.
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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From first two sentences, we have this equation

    V(t) = 50 - a*t.


representing the current volume V(t) as a function of time, t, in minutes,

and "a" is the constant leaking rate in liters per minute.



At t= 20 minutes,  

    V(20) = 40 = 50 - a*20,


which gives  a = %2850-40%29%2F20 = 10%2F20 = 0.5  liters per minute.



After further 30 minutes,  the volume of the water in the tank is

    V(50) = 40 - 0.5*30 = 40 - 15 = 25 liters.


So, 25 liters is 5% of the tank capacity.



Hence, the total capacity of the tank is  25%2F0.05 = 500 liters.



ANSWER.  The total capacity of the tank is  25%2F0.05 = 500 liters.

Solved,  answered,  explained and completed.