SOLUTION: The perimeter of a rectangle is P=2L+2W, where L is the length of the rectangle and W is the width. If the perimeter of a rectangle is 256 feet, and the width of the rectangle is 4
Algebra ->
Finance
-> SOLUTION: The perimeter of a rectangle is P=2L+2W, where L is the length of the rectangle and W is the width. If the perimeter of a rectangle is 256 feet, and the width of the rectangle is 4
Log On
Question 1165784: The perimeter of a rectangle is P=2L+2W, where L is the length of the rectangle and W is the width. If the perimeter of a rectangle is 256 feet, and the width of the rectangle is 48 feet, then what is the length of the rectangle? Answer by ikleyn(52787) (Show Source):