SOLUTION: 10% of the oil in tank was drawn out and if the tank was originally 2/3 full what fraction of tank is now empty.?.

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Question 1164328: 10% of the oil in tank was drawn out and if the tank was originally 2/3 full what fraction of tank is now empty.?.
Found 4 solutions by josgarithmetic, solver91311, jim_thompson5910, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
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2%2F3-%281%2F10%29%282%2F3%29
2%2F3-2%2F30
20%2F30-2%2F30
18%2F30
3%2F5-----------still in the tank
therefore2%2F5----------empty in the tank



------------------------(wrong fraction drawn out )--------------------
2%2F3-%282%2F5%29%282%2F3%29
%285%2F5%29%282%2F3%29-%282%2F5%29%282%2F3%29
10%2F15-4%2F15
6%2F15
2%2F5----------------------amount now full

Amount of tank now EMPTY, cross%283%2F5%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!



John

My calculator said it, I believe it, that settles it

Answer by jim_thompson5910(35256) About Me  (Show Source):
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Let's say we had a tank that was 30 gallons in total capacity.
I'm picking on 30 because it is the LCD of the fractions 1/10 and 2/3
Note: 1/10 = 0.10 = 10%

If the tank is 2/3 full, then (2/3)*30 = 20 gallons of gas is in the tank
Then 10% of that amount (20 gallons) is taken out, meaning we take out 0.10*20 = 2 gallons of gas. We then have 20-2 = 18 gallons left.

The amount of empty space is 30-18 = 12 gallons

The fraction of empty space is 12/30 = (6*2)/(6*5) = 2/5

Answer: 2/5

The tutor @josgarithmetic has the right idea, but somehow got the 2/5 and 3/5 mixed up I think.

Answer by ikleyn(52781) About Me  (Show Source):
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.

Originally, the tank was  2%2F3  full.


10% of this volume was drawn out.


It means that remaining  OIL volume in the tank  is  2%2F3 - %281%2F10%29%2A%282%2F3%29 = 20%2F30+-+2%2F30 = 18%2F30 = 3%2F5  of the full tank capacity.


Hence, the tank is  now  1 - 3%2F5 = 2%2F5  empty.    ANSWER


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The solution and the answer by @josgarithmetic  BOTH  ARE  WRONG.