SOLUTION: A box contained some red and green beads . 40% of beads were red. The red beads were increased by 25% and 20% of green beads were removed. As a result there were 200 red beads. How

Algebra ->  Finance -> SOLUTION: A box contained some red and green beads . 40% of beads were red. The red beads were increased by 25% and 20% of green beads were removed. As a result there were 200 red beads. How      Log On


   



Question 1164285: A box contained some red and green beads . 40% of beads were red. The red beads were increased by 25% and 20% of green beads were removed. As a result there were 200 red beads. How many red beads are there at first?..
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

            It is a tricky problem,  since many parts and many input data are unnecessary and were introduced
            with the only goal to confuse the reader.


Let X be the number of red beads initially.


When the number of red beads was increased by 25%, the number of red beads became  X + 0.25X = 1.25X.


We are given that this number is 200.  So


    1.25X = 200;  hence,  X = 200%2F1.25 = 160.


ANSWER.  Originally, were there 160 red beads in the container.

Solved.


As you see,  everything related to green beads is  IRRELEVANT.
The info saying  "40%  of beads were red"  is irrelevant,  too.

Thus to solve the problem,  all unnecessary data should be filtered out.