SOLUTION: John is 3 times as old as Ken. Three years ago, he is four times as old as Joy. Find the sum of their ages.

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Question 1160802: John is 3 times as old as Ken. Three years ago, he is four times as old as Joy. Find the sum of their ages.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
John 3k
Ken k
Joy j


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Three years ago, he is four times as old as Joy.
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"He" is "John".
Not "is", but "WAS".
3k-3=4%28j-3%29
3k-3=4j-12
3k=4j-9
not yet to answer the question.

I suspect either a mistake in the description, or some information was excluded.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

As posted, worded, printed and presented, the problem is DEFECTIVE.