SOLUTION: A baseball diamond is a square with sides of length 90 ft. A batter hits the ball and runs toward first base with a speed of 22 ft/s. At what rate is his distance from second b

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Question 1160419: A baseball diamond is a square with sides of length 90 ft. A batter hits the ball and runs toward first base with a speed of 22 ft/s.
At what rate is his distance from second base changing when he is halfway to first base?

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

This is a related-rates problem.
The distance h from the runner to 2nd base is +h+=+sqrt%2890%5E2+%2B+x%5E2%29+
where x is the remaining distance from the runner to 1st base.
Given:
dx%2Fdt+=+22+%28ft%2Fs%29+ but note that because the way I've defined x, it is decreasing. Therefore I will write +dx%2Fdt+=+-22+%28ft%2Fs%29+ so if we get a negative answer it indicates a decreasing distance.
[ If you instead insist on dx/dt > 0, you can say dx/dt=22 ft/s and define x as the distance from home plate to the runner, then the distance remaining to first base is 90-x and you end up with the minus sign later, but the math is a little uglier. ]
Using the chain rule:
= +%28-22x%29+%2F+sqrt%2890%5E2%2Bx%5E2%29+
Plugging in x=45 gives +highlight%28+dh%2Fdt+=+-9.839+%29+ ft/s
(The runner's distance with respect to 2nd base is decreasing at 9.839 ft/s)