SOLUTION: A baseball diamond is a square with sides of length 90 ft. A batter hits the ball and runs toward first base with a speed of 22 ft/s.
At what rate is his distance from second b
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-> SOLUTION: A baseball diamond is a square with sides of length 90 ft. A batter hits the ball and runs toward first base with a speed of 22 ft/s.
At what rate is his distance from second b
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Question 1160419: A baseball diamond is a square with sides of length 90 ft. A batter hits the ball and runs toward first base with a speed of 22 ft/s.
At what rate is his distance from second base changing when he is halfway to first base? Answer by math_helper(2461) (Show Source):
This is a related-rates problem.
The distance h from the runner to 2nd base is
where x is the remaining distance from the runner to 1st base.
Given: but note that because the way I've defined x, it is decreasing. Therefore I will write so if we get a negative answer it indicates a decreasing distance.
[ If you instead insist on dx/dt > 0, you can say dx/dt=22 ft/s and define x as the distance from home plate to the runner, then the distance remaining to first base is 90-x and you end up with the minus sign later, but the math is a little uglier. ]
Using the chain rule: =
Plugging in x=45 gives ft/s
(The runner's distance with respect to 2nd base is decreasing at 9.839 ft/s)