Question 1160367: A lawyer invested a certain amount of money in a restaurant business, expecting the earnings to be 9% per year. He invested thrice the amount in a retail business, expecting the earnings to be 11% per year. If after a year, the total interest from the investment is 63,000, how much did he invest in the restaurant business?
Found 3 solutions by ikleyn, MathTherapy, greenestamps:
Answer by ikleyn(52781)   (Show Source):
Answer by MathTherapy(10552)  (Show Source):
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A lawyer invested a certain amount of money in a restaurant business, expecting the earnings to be 9% per year. He invested thrice the amount in a retail business, expecting the earnings to be 11% per year. If after a year, the total interest from the investment is 63,000, how much did he invest in the restaurant business?
Let amount invested in the restaurant business be R
Then amount invested in the retail business, is 3R
We then get: .09R + .11(3R) = 63,000
.09R + .33R = 63,000
.42R = 63,000
Amount invested in the restaurant business, or 
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
Since the amount invested at 11% is 3 times the amount invested at 9%, the average rate of return is 10.5%.
$63,000 interest at 10.5% means the total invested was  .
One-quarter of the total was invested in the restaurant business.
ANSWER: 1/4 of $600,000, which is $150,000.
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