SOLUTION: Write an equation of a line that passes through the point (-1,2) and is perpendicular to the line y=1/2x-3.

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Question 1159250: Write an equation of a line that passes through the point (-1,2) and is perpendicular to the line y=1/2x-3.
Found 3 solutions by josgarithmetic, Boreal, MathLover1:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
perpendicular lines have slope products that are negative reciprocals of one another.
the slope of the given line is 1/2
the perpendicular line has slope -2
point slope formula y-y1=m(x-x1) m slope (x1, y1) point
y-2=-2(x+1)
y=-2x
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%281%2F2%29x-3%2C-2x%29

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

a line that passes through the point (-1,2) and is perpendicular to the line
y=%281%2F2%29x-3-> slope is m=1%2F2
perpendicular line will have a slope negative reciprocal to m=1%2F2
it is m=-1%2F%281%2F2%29=-2
use point slope formula:
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is a slope -2, x%5B1%5D and y%5B1%5D coordinates of given point (-1,2)

y-2=-2%28x-%28-1%29%29
y-2=-2%28x%2B1%29
y-2=-2x-2
y=-2x-2%2B2
y=-2x-> your equation