SOLUTION: A bacteria population increases from 20,000 to 50,000 in 8 days. Find a formula for the number of bacteria after t days. What is the continuous rate of increase?

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Question 1159240: A bacteria population increases from 20,000 to 50,000 in 8 days. Find a formula for the number of bacteria after t days. What is the continuous rate of increase?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by ikleyn(52781) About Me  (Show Source):
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The formula is  N(t) = 20000%2A%2850000%2F20000%29%5E%28t%2F8%29,  or,  equivalently,


    N(t) = 20000%2A%285%2F2%29%5E%28t%2F8%29.    ANSWER


The exponential daily growing factor is  %285%2F2%29%5E%281%2F8%29 = 1.121353.    ANSWER