Question 1157111: A line L1 passes through point[1,2]and has a gradient of 5.Another line L2 is perpendicular to L1 and meets it at Point x=4 .find the equation of L2 in the form y=mx+c
Found 3 solutions by mananth, ikleyn, greenestamps:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! y-2=5(x-1)
y-2 =5x-5
y=5x-3
Slope of perpendicular line will be (-1/5)
Passes through (4,0)
(y-y1)= m(x-x1)
(y-0)=(-1/5)(x-4)
y= (-1/5)x+(4/5)
Answer by ikleyn(53742)  (Show Source):
You can put this solution on YOUR website! A line L1 passes through point[1,2]and has a gradient of 5. Another line L2 is perpendicular to L1
and meets it at Point x = 4. Find the equation of L2 in the form y = mx + c
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The solution by @mananth in his post is incorrect.
He mistakenly assumed that line L2 passes through point (4,0),
but the problem states something totally different, instead.
See below my correct solution.
Line L1: y - 2 = 5*(x-1)
y = 5x - 5 + 2 = 5x - 3. (1)
Slope of L1 is 5.
Hence, slope L2 is -1/5.
L2 meets L1 at point x = 4, where y = 5*4 - 3 = 17, according to equation (1).
Thus, L2 has the slope -1/5 and passes through point (4,17)
Hence, an equation for L2 is
y - 17 =  ,
or
y - 17 =  +  ,
y = + 17. <<<---=== ANSWER
Solved correctly.
Answer by greenestamps(13325)  (Show Source):
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