Question 1138067: Brown sold his car for 3/5 of the cost price and finds that in doing so he has list £750 .How much did he sell the car?
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website!
if he sells the car for 750 and 750 was 3/5 of the cost, then the cost of the car would be 5/3 * 750 = 1250.
you would solve that as follows:
let x = the cost of the car.
3/5 * x = 750.
multiplhy both sides of this equation by 5/3 to get x = 5/3 * 750.
this makes x = 1250, which is the cost of the car.
if the cost of the car is 750 and he sells it for 3/5 of the cost, then he sells is for 3/5 * 750 = 450.
in that case, you would solve it as follows.
let x = the price he sold the car for.
than x = 3/5 * 750.
solve for x to get x = 450.
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