SOLUTION: How many numbers between 100 and 1000 are Not divisible by 2 Not divisible by 3 Not divisible by either 2 or 3 . Not quite an algebra one!

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Question 1137732: How many numbers between 100 and 1000 are
Not divisible by 2
Not divisible by 3
Not divisible by either 2 or 3 .
Not quite an algebra one!

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

            The formulation of the problem in the post leaves the room for questions

                is 100 included ?    Is 1000 included ?

            In this sense, this formulation is unprofessional.  A professional formulation of a Math problem does not leave
            the room for such questions.  Therefore,  I will reformulate the problem in this way:

            How many three-digit numbers are

              - Not divisible by 2 ?
              - Not divisible by 3 ?
              - Not divisible by either 2 or 3 ?

            Thre-digit numbers are the numbers from 100 to 999 inclusively, so there is no uncertainty with this formulation.


(a)   How many three-digit numbers are not divisible by 2 ?

  
     Every second integer number in the interval [100,999] is divisible by 2.

     The number of such pairs is  %28999-99%29%2F2 = 900%2F2 = 450.

     So, 450 of the 900 numbers are divisible by 2, and the rest, 900-450 = 450 ARE NOT divisible by 2.    ANSWER


(b)   How many three-digit numbers are not divisible by 3 ?

     Every third integer number in this interval is divisible by 3.

     More precisely, every third, starting from 102.

     The number of such triples is  %28998-101%29%2F3 = 299.

     To it, I must add 1 to account for the number 999, which goes individually, without companions.

     So, 300 = 299+1 of the 900 numbers are divisible by 3, and the rest, 900-300 = 600 ARE NOT divisible by 3.    ANSWER


(c)   How many three-digit numbers are not divisible by either 2 or 3 ?

     As a first approach, we can subtract 450 and 300 from 900 - those integer numbers that are divisible by 2 and by 3.

     900 - 450 - 300 = 150.

     But doing in this way, we subtract multiples of 6 twice (!).

     Therefore, we must return back the number of multiples of 6 among 3-digit numbers.

      Again, we need to calculate the number of segments of the length 6 from 100 to 999 inclusively.

      %28999-99%29%2F6 = 150.  

      Hence, the number of multiples to 6 between 100 and 999 is 150.

     Therefore, our final answer to question (c) is  150 + 150 = 300.      ANSWER

Solved.