SOLUTION: Water initially at 200F. is left in a room of temperature 60F to cool. After t minutes, the temperature T of the water is given by T(t) = 60 + 140e^ - 0.096t. Find t

Algebra ->  Finance -> SOLUTION: Water initially at 200F. is left in a room of temperature 60F to cool. After t minutes, the temperature T of the water is given by T(t) = 60 + 140e^ - 0.096t. Find t      Log On


   

Question 1136379: Water initially at 200F. is left in a room of temperature 60F to cool.
After t minutes, the temperature T of the water is given by
T(t) = 60 + 140e^ - 0.096t.
Find the temperature of the water 20 minutes after it is left to cool. (Round to the nearest tenth of a
degree.)
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Plug in the given number of minutes t and use your calculator.

Make sure the entire exponent is in parentheses:

60%2B140e%5E%28%28-0.096%2A20%29%29