SOLUTION: A spiral spring of natural 20cm has a scale pan hanging freely in its lower end. When an object if mass 40g is plated on it,its length becomes 21.80cm. When another object of mass

Algebra ->  Finance -> SOLUTION: A spiral spring of natural 20cm has a scale pan hanging freely in its lower end. When an object if mass 40g is plated on it,its length becomes 21.80cm. When another object of mass       Log On


   

Question 1131963: A spiral spring of natural 20cm has a scale pan hanging freely in its lower end. When an object if mass 40g is plated on it,its length becomes 21.80cm. When another object of mass 60g is placed on the pan,the length becomes 22.05cm. Calculate the mass of the scale pan.[g=10m/s squared]
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
The spring's constant k = deltaF%2FdeltaH = %28g%2Adelta_M%29%2FdeltaH = %2810%2A%280.060-0.040%29%29%2F%280.2205-0.2180%29 = 80 Newtons/meter.


Let M be the mass of the scale pan (in kilograms).  Then you have this equation to find M


(M + 0.040)*g = 80*(0.2180 - 0.20).


M = 80%2A%280.2180+-+0.20%29%2Fg - 0.040 = 80%2A%280.2180+-+0.20%29%2F10 - 0.040 = 0.104 kilograms = 104 grams.    ANSWER