SOLUTION: Solve the system 2x^2-4xy+16y^2=2 3x+4y=3

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Question 1131209: Solve the system
2x^2-4xy+16y^2=2
3x+4y=3
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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Solve the system
2x^2-4xy+16y^2=2
3x+4y=3
----------------------------

4y=3-3x
-
2x%5E2-4xy%2B16y%5E2=2
2x%5E2-4yx%2B16y%5E2=2
2x%5E2-%283x-3x%5E2%29%2B9-18x%2B9x%5E2=2
2x%5E2-3x%2B3x%5E2%2B9-18x%2B9x%5E2=2
14x%5E2-21x%2B7=0
2x%5E2-3x%2B1=0
%282x-1%29%28x-1%29=0
system%28x=1%2F2%2COR%2Cx=1%29
and you can find the y values corresponding to each of these x values.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the system
2x^2-4xy+16y^2=2
3x+4y=3
Correct answers: 

What the other person has conjured up will NEVER get you these answers, since the correct equation is NOT 14x2 - 21x + 19 = 0.

cross%2814x%5E2-21x%2B19=0%29 <======== WRONG, WRONG, WRONG

In other words, you DON'T have to finish anything since trying to finish will get you an answer that will be WRONG, all DAY LONG!!