SOLUTION: Math 9 theorem 3: the diagonals of a rhombus is perpendicular Proof!! Plss help me to answer the proof

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Question 1130860: Math 9 theorem 3: the diagonals of a rhombus is perpendicular
Proof!!
Plss help me to answer the proof
Answer by MathLover1(20850) About Me  (Show Source):
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proof: the diagonals are perpendicular to each other


assuming we have a rhombus ABCD with diagonals AC and BD intersecting at point E

AE ≅ CE..................as two halves of a diagonal AC

BE ≅ BE................. by reflexive property of congruence, a segment is congruent to itself
AB ≅ CB.....................as sides of a rhombus
Δ +AEB+ ≅ Δ CEB..........by SSS congruence
< AEB ≅ < CEB....................... corresponding angles
< AEB + < CEB=180°.........since they are supplementary angles
< AEB = < CEB=90°..........addition property of congruent angles
AC ⊥ BD..........the diagonals of ABCD are perpendicular to each other