Question 1130096: Question regarding the below example.
E and F are mutually exclusive and P(E) = 0.2 and P(F) = 0.5. Find P(E
U F).
If the two are mutually exclusive, using the addition rule, wouldn't P(E U F)=0.7? This is just a guess on my part as I don't know how to work through this type of problem.
Can someone please provide an explanation?
Thank you!
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
If the two are mutually exclusive, it means that P(E & F) = 0,
and then, using the general formula, you have
P(E U F) = P(E) + P(F) - P(E & F) = P(E) + P(F) - 0 = P(E) + P(F).
So, your suggestion is correct.
The other, more visual way to see it is to notice that if the sets E and F are mutually exclusive, then the sets E and F are disjoint.
Answer by MathLover1(20849)  (Show Source):
You can put this solution on YOUR website!
E and F are mutually exclusive and P(E) = 0.2 and P(F) = 0.5. Find P(E
U F).
To calculate the probability that either E or F occurs we evaluate
P(E∪F) =P(E) +P(F) = 0.2+0.5 = 0.7
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