SOLUTION: tim needs to fill three 20l barrels with oil. if his oil dispenser flows at 100 ml/s, how long will it take him to fill
the 3 containers? (in minutes)
John drove for 6 hours. I
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-> SOLUTION: tim needs to fill three 20l barrels with oil. if his oil dispenser flows at 100 ml/s, how long will it take him to fill
the 3 containers? (in minutes)
John drove for 6 hours. I
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Question 1126396: tim needs to fill three 20l barrels with oil. if his oil dispenser flows at 100 ml/s, how long will it take him to fill
the 3 containers? (in minutes)
John drove for 6 hours. In that time he managed to complete 2/6 of his journey.
What is the total length of his journey?
for both questions please show formulas (with equasions) and . . . . feel free to use algebra or decimals
Regarding the 2/6ths fraction can someone tell me if we change 6 to 1/6ths? Do they both have to be fractions to proceed? Can we convert both to decimals?
thanks Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website! ---------------------
tim needs to fill three 20l barrels with oil. if his oil dispenser flows at 100 ml/s, how long will it take him to fill
the 3 containers? (in minutes)
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This was was already given a response.
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John drove for 6 hours. In that time he managed to complete 2/6 of his journey.
What is the total length of his journey?
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Not enough information for total length of journey.
TIme: 6 hours
Rate: unknown
Distance: unknown; only of unknown journey length
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for both questions please show formulas (with equasions) and . . . . feel free to use algebra or decimals
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See above.
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Regarding the 2/6ths fraction can someone tell me if we change 6 to 1/6ths? Do they both have to be fractions to proceed? Can we convert both to decimals?
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?
What?
You can convert to a decimal form if you like.
1.00000 divided by 3;
Really meant as 1.00000, with repeating 0 digits, divided by whole number 3.
You can do the long-division procedure on your own unless you want help on this.
Result is 0.33333333333 repeating the digit 3 without end.
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